10+2(n-3)=3(n+4)-14

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Solution for 10+2(n-3)=3(n+4)-14 equation: 



10+2(n-3)=3(n+4)-14

We move all terms to the left:

10+2(n-3)-(3(n+4)-14)=0

We multiply parentheses

2n-(3(n+4)-14)-6+10=0



We calculate terms in parentheses: -(3(n+4)-14), so:

3(n+4)-14

We multiply parentheses

3n+12-14

We add all the numbers together, and all the variables

3n-2

Back to the equation:

-(3n-2)



We add all the numbers together, and all the variables

2n-(3n-2)+4=0

We get rid of parentheses

2n-3n+2+4=0

We add all the numbers together, and all the variables

-1n+6=0

We move all terms containing n to the left, all other terms to the right

-n=-6

n=-6/-1

n=+6

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