10+2(v-9)=3(v+1)-6

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Solution for 10+2(v-9)=3(v+1)-6 equation: 



10+2(v-9)=3(v+1)-6

We move all terms to the left:

10+2(v-9)-(3(v+1)-6)=0

We multiply parentheses

2v-(3(v+1)-6)-18+10=0



We calculate terms in parentheses: -(3(v+1)-6), so:

3(v+1)-6

We multiply parentheses

3v+3-6

We add all the numbers together, and all the variables

3v-3

Back to the equation:

-(3v-3)



We add all the numbers together, and all the variables

2v-(3v-3)-8=0

We get rid of parentheses

2v-3v+3-8=0

We add all the numbers together, and all the variables

-1v-5=0

We move all terms containing v to the left, all other terms to the right

-v=5

v=5/-1

v=-5

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