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10+2(x+1)=4x-4(2x-2)
We move all terms to the left:
10+2(x+1)-(4x-4(2x-2))=0
We multiply parentheses
2x-(4x-4(2x-2))+2+10=0
We calculate terms in parentheses: -(4x-4(2x-2)), so:We add all the numbers together, and all the variables
4x-4(2x-2)
We multiply parentheses
4x-8x+8
We add all the numbers together, and all the variables
-4x+8
Back to the equation:
-(-4x+8)
2x-(-4x+8)+12=0
We get rid of parentheses
2x+4x-8+12=0
We add all the numbers together, and all the variables
6x+4=0
We move all terms containing x to the left, all other terms to the right
6x=-4
x=-4/6
x=-2/3
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