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10+2(x-3)=12-3(3x-1)
We move all terms to the left:
10+2(x-3)-(12-3(3x-1))=0
We multiply parentheses
2x-(12-3(3x-1))-6+10=0
We calculate terms in parentheses: -(12-3(3x-1)), so:We add all the numbers together, and all the variables
12-3(3x-1)
determiningTheFunctionDomain -3(3x-1)+12
We multiply parentheses
-9x+3+12
We add all the numbers together, and all the variables
-9x+15
Back to the equation:
-(-9x+15)
2x-(-9x+15)+4=0
We get rid of parentheses
2x+9x-15+4=0
We add all the numbers together, and all the variables
11x-11=0
We move all terms containing x to the left, all other terms to the right
11x=11
x=11/11
x=1
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