10+2(z-9)=3(z+1)

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Solution for 10+2(z-9)=3(z+1) equation: 



10+2(z-9)=3(z+1)

We move all terms to the left:

10+2(z-9)-(3(z+1))=0

We multiply parentheses

2z-(3(z+1))-18+10=0



We calculate terms in parentheses: -(3(z+1)), so:

3(z+1)

We multiply parentheses

3z+3

Back to the equation:

-(3z+3)



We add all the numbers together, and all the variables

2z-(3z+3)-8=0

We get rid of parentheses

2z-3z-3-8=0

We add all the numbers together, and all the variables

-1z-11=0

We move all terms containing z to the left, all other terms to the right

-z=11

z=11/-1

z=-11

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