10+2(z-9)=3(z+1)-6

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Solution for 10+2(z-9)=3(z+1)-6 equation:


Simplifying
10 + 2(z + -9) = 3(z + 1) + -6

Reorder the terms:
10 + 2(-9 + z) = 3(z + 1) + -6
10 + (-9 * 2 + z * 2) = 3(z + 1) + -6
10 + (-18 + 2z) = 3(z + 1) + -6

Combine like terms: 10 + -18 = -8
-8 + 2z = 3(z + 1) + -6

Reorder the terms:
-8 + 2z = 3(1 + z) + -6
-8 + 2z = (1 * 3 + z * 3) + -6
-8 + 2z = (3 + 3z) + -6

Reorder the terms:
-8 + 2z = 3 + -6 + 3z

Combine like terms: 3 + -6 = -3
-8 + 2z = -3 + 3z

Solving
-8 + 2z = -3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-8 + 2z + -3z = -3 + 3z + -3z

Combine like terms: 2z + -3z = -1z
-8 + -1z = -3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-8 + -1z = -3 + 0
-8 + -1z = -3

Add '8' to each side of the equation.
-8 + 8 + -1z = -3 + 8

Combine like terms: -8 + 8 = 0
0 + -1z = -3 + 8
-1z = -3 + 8

Combine like terms: -3 + 8 = 5
-1z = 5

Divide each side by '-1'.
z = -5

Simplifying
z = -5

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