10+2/3j=52

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Solution for 10+2/3j=52 equation:



10+2/3j=52
We move all terms to the left:
10+2/3j-(52)=0
Domain of the equation: 3j!=0
j!=0/3
j!=0
j∈R
We add all the numbers together, and all the variables
2/3j-42=0
We multiply all the terms by the denominator
-42*3j+2=0
Wy multiply elements
-126j+2=0
We move all terms containing j to the left, all other terms to the right
-126j=-2
j=-2/-126
j=1/63

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