10+3(2x+5)-3(x+2)=37

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Solution for 10+3(2x+5)-3(x+2)=37 equation: 



10+3(2x+5)-3(x+2)=37

We move all terms to the left:

10+3(2x+5)-3(x+2)-(37)=0

We add all the numbers together, and all the variables

3(2x+5)-3(x+2)-27=0

We multiply parentheses

6x-3x+15-6-27=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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