10+3(2x-4)=17-(x+5)

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Solution for 10+3(2x-4)=17-(x+5) equation: 



10+3(2x-4)=17-(x+5)

We move all terms to the left:

10+3(2x-4)-(17-(x+5))=0

We multiply parentheses

6x-(17-(x+5))-12+10=0



We calculate terms in parentheses: -(17-(x+5)), so:

17-(x+5)

determiningTheFunctionDomain
-(x+5)+17

We get rid of parentheses

-x-5+17

We add all the numbers together, and all the variables

-1x+12

Back to the equation:

-(-1x+12)



We add all the numbers together, and all the variables

6x-(-1x+12)-2=0

We get rid of parentheses

6x+1x-12-2=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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