10+3(t-3)=28

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Solution for 10+3(t-3)=28 equation: 



10+3(t-3)=28

We move all terms to the left:

10+3(t-3)-(28)=0

We add all the numbers together, and all the variables

3(t-3)-18=0

We multiply parentheses

3t-9-18=0

We add all the numbers together, and all the variables

3t-27=0

We move all terms containing t to the left, all other terms to the right

3t=27

t=27/3

t=9

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