10+3(x-2)=7x+20

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Solution for 10+3(x-2)=7x+20 equation: 



10+3(x-2)=7x+20

We move all terms to the left:

10+3(x-2)-(7x+20)=0

We multiply parentheses

3x-(7x+20)-6+10=0

We get rid of parentheses

3x-7x-20-6+10=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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