10+3(x-5)=-9(2x-3)+5x

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Solution for 10+3(x-5)=-9(2x-3)+5x equation: 



10+3(x-5)=-9(2x-3)+5x

We move all terms to the left:

10+3(x-5)-(-9(2x-3)+5x)=0

We multiply parentheses

3x-(-9(2x-3)+5x)-15+10=0



We calculate terms in parentheses: -(-9(2x-3)+5x), so:

-9(2x-3)+5x

We add all the numbers together, and all the variables

5x-9(2x-3)

We multiply parentheses

5x-18x+27

We add all the numbers together, and all the variables

-13x+27

Back to the equation:

-(-13x+27)



We add all the numbers together, and all the variables

3x-(-13x+27)-5=0

We get rid of parentheses

3x+13x-27-5=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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