10+3x+2(x-3)=28

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Solution for 10+3x+2(x-3)=28 equation: 



10+3x+2(x-3)=28

We move all terms to the left:

10+3x+2(x-3)-(28)=0

We add all the numbers together, and all the variables

3x+2(x-3)-18=0

We multiply parentheses

3x+2x-6-18=0

We add all the numbers together, and all the variables

5x-24=0

We move all terms containing x to the left, all other terms to the right

5x=24

x=24/5

x=4+4/5

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