10+3x=2(-x+4)-23

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Solution for 10+3x=2(-x+4)-23 equation: 



10+3x=2(-x+4)-23

We move all terms to the left:

10+3x-(2(-x+4)-23)=0

We add all the numbers together, and all the variables

3x-(2(-1x+4)-23)+10=0



We calculate terms in parentheses: -(2(-1x+4)-23), so:

2(-1x+4)-23

We multiply parentheses

-2x+8-23

We add all the numbers together, and all the variables

-2x-15

Back to the equation:

-(-2x-15)



We get rid of parentheses

3x+2x+15+10=0

We add all the numbers together, and all the variables

5x+25=0

We move all terms containing x to the left, all other terms to the right

5x=-25

x=-25/5

x=-5

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