10+3x=2(-x+4)-23

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Solution for 10+3x=2(-x+4)-23 equation:



10+3x=2(-x+4)-23
We move all terms to the left:
10+3x-(2(-x+4)-23)=0
We add all the numbers together, and all the variables
3x-(2(-1x+4)-23)+10=0
We calculate terms in parentheses: -(2(-1x+4)-23), so:
2(-1x+4)-23
We multiply parentheses
-2x+8-23
We add all the numbers together, and all the variables
-2x-15
Back to the equation:
-(-2x-15)
We get rid of parentheses
3x+2x+15+10=0
We add all the numbers together, and all the variables
5x+25=0
We move all terms containing x to the left, all other terms to the right
5x=-25
x=-25/5
x=-5

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