10+4(7-5x)=32-18x

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Solution for 10+4(7-5x)=32-18x equation: 



10+4(7-5x)=32-18x

We move all terms to the left:

10+4(7-5x)-(32-18x)=0

We add all the numbers together, and all the variables

4(-5x+7)-(-18x+32)+10=0

We multiply parentheses

-20x-(-18x+32)+28+10=0

We get rid of parentheses

-20x+18x-32+28+10=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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