10+4x=2(-x+5)-18

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Solution for 10+4x=2(-x+5)-18 equation: 



10+4x=2(-x+5)-18

We move all terms to the left:

10+4x-(2(-x+5)-18)=0

We add all the numbers together, and all the variables

4x-(2(-1x+5)-18)+10=0



We calculate terms in parentheses: -(2(-1x+5)-18), so:

2(-1x+5)-18

We multiply parentheses

-2x+10-18

We add all the numbers together, and all the variables

-2x-8

Back to the equation:

-(-2x-8)



We get rid of parentheses

4x+2x+8+10=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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