10+4x=50/x-10+2x

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Solution for 10+4x=50/x-10+2x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x+10 = 2*x+50/x-10 // - 2*x+50/x-10

4*x-(2*x)-(50/x)+10+10 = 0

4*x-2*x-50*x^-1+10+10 = 0

2*x^1-50*x^-1+20*x^0 = 0

(2*x^2+20*x^1-50*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2+20*x^1-50*x^0) = 0

x^1

2*x^2+20*x-50 = 0

2*x^2+20*x-50 = 0

DELTA = 20^2-(-50*2*4)

DELTA = 800

DELTA > 0

x = (800^(1/2)-20)/(2*2) or x = (-800^(1/2)-20)/(2*2)

x = (20*2^(1/2)-20)/4 or x = (-20*2^(1/2)-20)/4

x in { (-20*2^(1/2)-20)/4, (20*2^(1/2)-20)/4}

x in { (-20*2^(1/2)-20)/4, (20*2^(1/2)-20)/4 }

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