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10+4x=x+3(5+x)
We move all terms to the left:
10+4x-(x+3(5+x))=0
We add all the numbers together, and all the variables
4x-(x+3(x+5))+10=0
We calculate terms in parentheses: -(x+3(x+5)), so:We get rid of parentheses
x+3(x+5)
We multiply parentheses
x+3x+15
We add all the numbers together, and all the variables
4x+15
Back to the equation:
-(4x+15)
4x-4x-15+10=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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