10+4y=2(3-y)

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Solution for 10+4y=2(3-y) equation: 



10+4y=2(3-y)

We move all terms to the left:

10+4y-(2(3-y))=0

We add all the numbers together, and all the variables

4y-(2(-1y+3))+10=0



We calculate terms in parentheses: -(2(-1y+3)), so:

2(-1y+3)

We multiply parentheses

-2y+6

Back to the equation:

-(-2y+6)



We get rid of parentheses

4y+2y-6+10=0

We add all the numbers together, and all the variables

6y+4=0

We move all terms containing y to the left, all other terms to the right

6y=-4

y=-4/6

y=-2/3

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