10+5(4w-3)=-30+10(5w+6)

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Solution for 10+5(4w-3)=-30+10(5w+6) equation: 



10+5(4w-3)=-30+10(5w+6)

We move all terms to the left:

10+5(4w-3)-(-30+10(5w+6))=0

We multiply parentheses

20w-(-30+10(5w+6))-15+10=0



We calculate terms in parentheses: -(-30+10(5w+6)), so:

-30+10(5w+6)

determiningTheFunctionDomain
10(5w+6)-30

We multiply parentheses

50w+60-30

We add all the numbers together, and all the variables

50w+30

Back to the equation:

-(50w+30)



We add all the numbers together, and all the variables

20w-(50w+30)-5=0

We get rid of parentheses

20w-50w-30-5=0

We add all the numbers together, and all the variables

-30w-35=0

We move all terms containing w to the left, all other terms to the right

-30w=35

w=35/-30

w=-1+1/6

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