10+5(b-3)=3(b+1)

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Solution for 10+5(b-3)=3(b+1) equation:


Simplifying
10 + 5(b + -3) = 3(b + 1)

Reorder the terms:
10 + 5(-3 + b) = 3(b + 1)
10 + (-3 * 5 + b * 5) = 3(b + 1)
10 + (-15 + 5b) = 3(b + 1)

Combine like terms: 10 + -15 = -5
-5 + 5b = 3(b + 1)

Reorder the terms:
-5 + 5b = 3(1 + b)
-5 + 5b = (1 * 3 + b * 3)
-5 + 5b = (3 + 3b)

Solving
-5 + 5b = 3 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-5 + 5b + -3b = 3 + 3b + -3b

Combine like terms: 5b + -3b = 2b
-5 + 2b = 3 + 3b + -3b

Combine like terms: 3b + -3b = 0
-5 + 2b = 3 + 0
-5 + 2b = 3

Add '5' to each side of the equation.
-5 + 5 + 2b = 3 + 5

Combine like terms: -5 + 5 = 0
0 + 2b = 3 + 5
2b = 3 + 5

Combine like terms: 3 + 5 = 8
2b = 8

Divide each side by '2'.
b = 4

Simplifying
b = 4

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