10+5=5(1/2x+2)

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Solution for 10+5=5(1/2x+2) equation: 



10+5=5(1/2x+2)

We move all terms to the left:

10+5-(5(1/2x+2))=0



Domain of the equation: 2x+2))!=0

x∈R



We add all the numbers together, and all the variables

-(5(1/2x+2))+15=0

We multiply all the terms by the denominator


-(5(1+15*2x+2))=0



We calculate terms in parentheses: -(5(1+15*2x+2)), so:

5(1+15*2x+2)

We add all the numbers together, and all the variables

5(15*2x+3)

We multiply parentheses

150x+15

Back to the equation:

-(150x+15)



We get rid of parentheses

-150x-15=0

We move all terms containing x to the left, all other terms to the right

-150x=15

x=15/-150

x=-1/10

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