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10+5x(x=2)
We move all terms to the left:
10+5x(x-(2))=0
We multiply parentheses
5x^2-10x+10=0
a = 5; b = -10; c = +10;
Δ = b2-4ac
Δ = -102-4·5·10
Δ = -100
Delta is less than zero, so there is no solution for the equation
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