10+6(-9-4x)=(x-12)+8

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Solution for 10+6(-9-4x)=(x-12)+8 equation: 



10+6(-9-4x)=(x-12)+8

We move all terms to the left:

10+6(-9-4x)-((x-12)+8)=0

We add all the numbers together, and all the variables

6(-4x-9)-((x-12)+8)+10=0

We multiply parentheses

-24x-((x-12)+8)-54+10=0



We calculate terms in parentheses: -((x-12)+8), so:

(x-12)+8

We get rid of parentheses

x-12+8

We add all the numbers together, and all the variables

x-4

Back to the equation:

-(x-4)



We add all the numbers together, and all the variables

-24x-(x-4)-44=0

We get rid of parentheses

-24x-x+4-44=0

We add all the numbers together, and all the variables

-25x-40=0

We move all terms containing x to the left, all other terms to the right

-25x=40

x=40/-25

x=-1+3/5

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