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10+a=3(2+a)
We move all terms to the left:
10+a-(3(2+a))=0
We add all the numbers together, and all the variables
a-(3(a+2))+10=0
We calculate terms in parentheses: -(3(a+2)), so:We get rid of parentheses
3(a+2)
We multiply parentheses
3a+6
Back to the equation:
-(3a+6)
a-3a-6+10=0
We add all the numbers together, and all the variables
-2a+4=0
We move all terms containing a to the left, all other terms to the right
-2a=-4
a=-4/-2
a=+2
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