10+x-3(x-2)+12(x-4)=2(x+5)+2x

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Solution for 10+x-3(x-2)+12(x-4)=2(x+5)+2x equation:


10+x-3(x-2)+12(x-4)=2(x+5)+2x

We simplify the equation to the form, which is simple to understand
10+x-3(x-2)+12(x-4)=2(x+5)+2x

Reorder the terms in parentheses
10+x+(-3x+6)+12*(x-4)=2*(x+5)+2x

Remove unnecessary parentheses
+10+x-3x+6+12+*(+x-4+)=+2+*(+x+5+)+2x

Reorder the terms in parentheses
10+x-3x+6+(+12x-48)=2*(x+5)+2x

Remove unnecessary parentheses
+10+x-3x+6+12x-48=+2+*(+x+5+)+2x

Reorder the terms in parentheses
10+x-3x+6+12x-48=+(+2x+10)+2x

Remove unnecessary parentheses
+10+x-3x+6+12x-48=+2x+10+2x

We move all terms containing x to the left and all other terms to the right.
+1x-3x+12x-2x-2x=+10-10-6+48

We simplify left and right side of the equation.
+6x=+42

We divide both sides of the equation by 6 to get x.
x=7

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