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10+x=13+(x/2)
We move all terms to the left:
10+x-(13+(x/2))=0
We add all the numbers together, and all the variables
x-(13+(+x/2))+10=0
We multiply all the terms by the denominator
x*2))-(13+(+x+10*2))=0
We add all the numbers together, and all the variables
x*2))-(13+(x+20))=0
We add all the numbers together, and all the variables
x*2))-(13+(x=0
Wy multiply elements
2x^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{4}=0$
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