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x in (-oo:+oo)
x+10 = 5*((1/5)*x+2) // - 5*((1/5)*x+2)
x-(5*((1/5)*x+2))+10 = 0
x-5*((1/5)*x+2)+10 = 0
x-5*(1/5*x+2)+10 = 0
x-5*(1/5*x+2)+10 = 0
10-10 = 0
0 = 0
0 = 0
x belongs to the empty set
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