10-((3x-1)/2)=(6x+3)/11

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Solution for 10-((3x-1)/2)=(6x+3)/11 equation: 



10-((3x-1)/2)=(6x+3)/11

We move all terms to the left:

10-((3x-1)/2)-((6x+3)/11)=0

We calculate fractions


(-33x+11)/()+(-12x-6)/()+10=0

We multiply all the terms by the denominator


(-33x+11)+(-12x-6)+10*()=0

We add all the numbers together, and all the variables

(-33x+11)+(-12x-6)=0

We get rid of parentheses

-33x-12x+11-6=0

We add all the numbers together, and all the variables

-45x+5=0

We move all terms containing x to the left, all other terms to the right

-45x=-5

x=-5/-45

x=1/9

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