10-(2+10y-4y-20)=-6y+10-(9y-9-5y+3)

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Solution for 10-(2+10y-4y-20)=-6y+10-(9y-9-5y+3) equation: 



10-(2+10y-4y-20)=-6y+10-(9y-9-5y+3)

We move all terms to the left:

10-(2+10y-4y-20)-(-6y+10-(9y-9-5y+3))=0

We add all the numbers together, and all the variables

-(6y-18)-(-6y+10-(4y-6))+10=0

We get rid of parentheses

-6y-(-6y+10-(4y-6))+18+10=0



We calculate terms in parentheses: -(-6y+10-(4y-6)), so:

-6y+10-(4y-6)

determiningTheFunctionDomain
-6y-(4y-6)+10

We get rid of parentheses

-6y-4y+6+10

We add all the numbers together, and all the variables

-10y+16

Back to the equation:

-(-10y+16)



We add all the numbers together, and all the variables

-6y-(-10y+16)+28=0

We get rid of parentheses

-6y+10y-16+28=0

We add all the numbers together, and all the variables

4y+12=0

We move all terms containing y to the left, all other terms to the right

4y=-12

y=-12/4

y=-3

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