10-(2n+3)=-1/2(4n-14)

Solution for 10-(2n+3)=-1/2(4n-14) equation:

10-(2n+3)=-1/2(4n-14)

We move all terms to the left:

10-(2n+3)-(-1/2(4n-14))=0


Domain of the equation: 2(4n-14))!=0

n∈R


We get rid of parentheses

-2n-(-1/2(4n-14))-3+10=0

We multiply all the terms by the denominator


-2n*2(4n-14))-(-3*2(4n-14))+10*2(4n-1-14))=0

We add all the numbers together, and all the variables

-2n*2(4n-14))-(-3*2(4n-14))+10*2(4n-15))=0

We add all the numbers together, and all the variables

-2n*2(4n-14))-(-3*2(4n-14))+10*2(4n=0

Wy multiply elements

-4n^2(4-12n^2(4=0