10-(2x-20)=(-5x-20)-50

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Solution for 10-(2x-20)=(-5x-20)-50 equation: 



10-(2x-20)=(-5x-20)-50

We move all terms to the left:

10-(2x-20)-((-5x-20)-50)=0

We get rid of parentheses

-2x-((-5x-20)-50)+20+10=0



We calculate terms in parentheses: -((-5x-20)-50), so:

(-5x-20)-50

We get rid of parentheses

-5x-20-50

We add all the numbers together, and all the variables

-5x-70

Back to the equation:

-(-5x-70)



We add all the numbers together, and all the variables

-2x-(-5x-70)+30=0

We get rid of parentheses

-2x+5x+70+30=0

We add all the numbers together, and all the variables

3x+100=0

We move all terms containing x to the left, all other terms to the right

3x=-100

x=-100/3

x=-33+1/3

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