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10-(2x-5)=5x-3(x-5)
We move all terms to the left:
10-(2x-5)-(5x-3(x-5))=0
We get rid of parentheses
-2x-(5x-3(x-5))+5+10=0
We calculate terms in parentheses: -(5x-3(x-5)), so:We add all the numbers together, and all the variables
5x-3(x-5)
We multiply parentheses
5x-3x+15
We add all the numbers together, and all the variables
2x+15
Back to the equation:
-(2x+15)
-2x-(2x+15)+15=0
We get rid of parentheses
-2x-2x-15+15=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0
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