10-(2x-5)=6+4(3x+8)

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Solution for 10-(2x-5)=6+4(3x+8) equation: 



10-(2x-5)=6+4(3x+8)

We move all terms to the left:

10-(2x-5)-(6+4(3x+8))=0

We get rid of parentheses

-2x-(6+4(3x+8))+5+10=0



We calculate terms in parentheses: -(6+4(3x+8)), so:

6+4(3x+8)

determiningTheFunctionDomain
4(3x+8)+6

We multiply parentheses

12x+32+6

We add all the numbers together, and all the variables

12x+38

Back to the equation:

-(12x+38)



We add all the numbers together, and all the variables

-2x-(12x+38)+15=0

We get rid of parentheses

-2x-12x-38+15=0

We add all the numbers together, and all the variables

-14x-23=0

We move all terms containing x to the left, all other terms to the right

-14x=23

x=23/-14

x=-1+9/14

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