10-(2y-4)+3y=12

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Solution for 10-(2y-4)+3y=12 equation:



10-(2y-4)+3y=12
We move all terms to the left:
10-(2y-4)+3y-(12)=0
We add all the numbers together, and all the variables
3y-(2y-4)-2=0
We get rid of parentheses
3y-2y+4-2=0
We add all the numbers together, and all the variables
y+2=0
We move all terms containing y to the left, all other terms to the right
y=-2

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