10-(2y-4)+3y=12

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Solution for 10-(2y-4)+3y=12 equation: 



10-(2y-4)+3y=12

We move all terms to the left:

10-(2y-4)+3y-(12)=0

We add all the numbers together, and all the variables

3y-(2y-4)-2=0

We get rid of parentheses

3y-2y+4-2=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2

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