10-(3-2x)(3+2x)=5

Solution for 10-(3-2x)(3+2x)=5 equation:

Simplifying
10 + -1(3 + -2x)(3 + 2x) = 5

Multiply (3 + -2x) * (3 + 2x)
10 + -1(3(3 + 2x) + -2x * (3 + 2x)) = 5
10 + -1((3 * 3 + 2x * 3) + -2x * (3 + 2x)) = 5
10 + -1((9 + 6x) + -2x * (3 + 2x)) = 5
10 + -1(9 + 6x + (3 * -2x + 2x * -2x)) = 5
10 + -1(9 + 6x + (-6x + -4x2)) = 5

Combine like terms: 6x + -6x = 0
10 + -1(9 + 0 + -4x2) = 5
10 + -1(9 + -4x2) = 5
10 + (9 * -1 + -4x2 * -1) = 5
10 + (-9 + 4x2) = 5

Combine like terms: 10 + -9 = 1
1 + 4x2 = 5

Solving
1 + 4x2 = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 4x2 = 5 + -1

Combine like terms: 1 + -1 = 0
0 + 4x2 = 5 + -1
4x2 = 5 + -1

Combine like terms: 5 + -1 = 4
4x2 = 4

Divide each side by '4'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}