10-(3-2y)=8y-5

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Solution for 10-(3-2y)=8y-5 equation: 



10-(3-2y)=8y-5

We move all terms to the left:

10-(3-2y)-(8y-5)=0

We add all the numbers together, and all the variables

-(-2y+3)-(8y-5)+10=0

We get rid of parentheses

2y-8y-3+5+10=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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