10-(3x/2)=16x=

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Solution for 10-(3x/2)=16x= equation: 



10-(3x/2)=16x=

We move all terms to the left:

10-(3x/2)-(16x)=0

We add all the numbers together, and all the variables

-(+3x/2)-16x+10=0

We add all the numbers together, and all the variables

-16x-(+3x/2)+10=0

We get rid of parentheses

-16x-3x/2+10=0

We multiply all the terms by the denominator


-16x*2-3x+10*2=0

We add all the numbers together, and all the variables

-3x-16x*2+20=0

Wy multiply elements

-3x-32x+20=0

We add all the numbers together, and all the variables

-35x+20=0

We move all terms containing x to the left, all other terms to the right

-35x=-20

x=-20/-35

x=4/7

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