10-(4-3x)+5x=6(2x-1)+8

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Solution for 10-(4-3x)+5x=6(2x-1)+8 equation: 



10-(4-3x)+5x=6(2x-1)+8

We move all terms to the left:

10-(4-3x)+5x-(6(2x-1)+8)=0

We add all the numbers together, and all the variables

-(-3x+4)+5x-(6(2x-1)+8)+10=0

We add all the numbers together, and all the variables

5x-(-3x+4)-(6(2x-1)+8)+10=0

We get rid of parentheses

5x+3x-(6(2x-1)+8)-4+10=0



We calculate terms in parentheses: -(6(2x-1)+8), so:

6(2x-1)+8

We multiply parentheses

12x-6+8

We add all the numbers together, and all the variables

12x+2

Back to the equation:

-(12x+2)



We add all the numbers together, and all the variables

8x-(12x+2)+6=0

We get rid of parentheses

8x-12x-2+6=0

We add all the numbers together, and all the variables

-4x+4=0

We move all terms containing x to the left, all other terms to the right

-4x=-4

x=-4/-4

x=1

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