10-(5/18)n=6+(1/6)n

Solution for 10-(5/18)n=6+(1/6)n equation:

10-(5/18)n=6+(1/6)n

We move all terms to the left:

10-(5/18)n-(6+(1/6)n)=0


Domain of the equation: 18)n!=0

n!=0/1

n!=0

n∈R



Domain of the equation: 6)n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

-(+5/18)n-(6+(+1/6)n)+10=0

We multiply parentheses

-5n^2-(6+(+1/6)n)+10=0

We multiply all the terms by the denominator


-5n^2*6)n)-(6+(+10*6)n)+1=0

We add all the numbers together, and all the variables

-5n^2*6)n)-(6+60n)+1=0

Wy multiply elements

-30n^3=0

We do not support enpression: n^3