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10-(6/5)d=-16
We move all terms to the left:
10-(6/5)d-(-16)=0
Domain of the equation: 5)d!=0We add all the numbers together, and all the variables
d!=0/1
d!=0
d∈R
-(+6/5)d+10-(-16)=0
We add all the numbers together, and all the variables
-(+6/5)d+26=0
We multiply parentheses
-6d^2+26=0
a = -6; b = 0; c = +26;
Δ = b2-4ac
Δ = 02-4·(-6)·26
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{39}}{2*-6}=\frac{0-4\sqrt{39}}{-12} =-\frac{4\sqrt{39}}{-12} =-\frac{\sqrt{39}}{-3} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{39}}{2*-6}=\frac{0+4\sqrt{39}}{-12} =\frac{4\sqrt{39}}{-12} =\frac{\sqrt{39}}{-3} $
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