10-(6/5)d=-16

Solution for 10-(6/5)d=-16 equation:

10-(6/5)d=-16

We move all terms to the left:

10-(6/5)d-(-16)=0


Domain of the equation: 5)d!=0

d!=0/1

d!=0

d∈R


We add all the numbers together, and all the variables

-(+6/5)d+10-(-16)=0

We add all the numbers together, and all the variables

-(+6/5)d+26=0

We multiply parentheses

-6d^2+26=0

a = -6; b = 0; c = +26;
Δ = b2-4ac
Δ = 02-4·(-6)·26
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{39}}{2*-6}=\frac{0-4\sqrt{39}}{-12}
=-\frac{4\sqrt{39}}{-12}
=-\frac{\sqrt{39}}{-3}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{39}}{2*-6}=\frac{0+4\sqrt{39}}{-12}
=\frac{4\sqrt{39}}{-12}
=\frac{\sqrt{39}}{-3}
$