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10-(d-2)=2(2d+1)
We move all terms to the left:
10-(d-2)-(2(2d+1))=0
We get rid of parentheses
-d-(2(2d+1))+2+10=0
We calculate terms in parentheses: -(2(2d+1)), so:We add all the numbers together, and all the variables
2(2d+1)
We multiply parentheses
4d+2
Back to the equation:
-(4d+2)
-1d-(4d+2)+12=0
We get rid of parentheses
-1d-4d-2+12=0
We add all the numbers together, and all the variables
-5d+10=0
We move all terms containing d to the left, all other terms to the right
-5d=-10
d=-10/-5
d=+2
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