10-(d-2)=2(2d+1)

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Solution for 10-(d-2)=2(2d+1) equation: 



10-(d-2)=2(2d+1)

We move all terms to the left:

10-(d-2)-(2(2d+1))=0

We get rid of parentheses

-d-(2(2d+1))+2+10=0



We calculate terms in parentheses: -(2(2d+1)), so:

2(2d+1)

We multiply parentheses

4d+2

Back to the equation:

-(4d+2)



We add all the numbers together, and all the variables

-1d-(4d+2)+12=0

We get rid of parentheses

-1d-4d-2+12=0

We add all the numbers together, and all the variables

-5d+10=0

We move all terms containing d to the left, all other terms to the right

-5d=-10

d=-10/-5

d=+2

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