10-(n-5)=5(n+2)

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Solution for 10-(n-5)=5(n+2) equation: 



10-(n-5)=5(n+2)

We move all terms to the left:

10-(n-5)-(5(n+2))=0

We get rid of parentheses

-n-(5(n+2))+5+10=0



We calculate terms in parentheses: -(5(n+2)), so:

5(n+2)

We multiply parentheses

5n+10

Back to the equation:

-(5n+10)



We add all the numbers together, and all the variables

-1n-(5n+10)+15=0

We get rid of parentheses

-1n-5n-10+15=0

We add all the numbers together, and all the variables

-6n+5=0

We move all terms containing n to the left, all other terms to the right

-6n=-5

n=-5/-6

n=5/6

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