10-(r+3)=2(r+5)

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Solution for 10-(r+3)=2(r+5) equation:


Simplifying
10 + -1(r + 3) = 2(r + 5)

Reorder the terms:
10 + -1(3 + r) = 2(r + 5)
10 + (3 * -1 + r * -1) = 2(r + 5)
10 + (-3 + -1r) = 2(r + 5)

Combine like terms: 10 + -3 = 7
7 + -1r = 2(r + 5)

Reorder the terms:
7 + -1r = 2(5 + r)
7 + -1r = (5 * 2 + r * 2)
7 + -1r = (10 + 2r)

Solving
7 + -1r = 10 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.
7 + -1r + -2r = 10 + 2r + -2r

Combine like terms: -1r + -2r = -3r
7 + -3r = 10 + 2r + -2r

Combine like terms: 2r + -2r = 0
7 + -3r = 10 + 0
7 + -3r = 10

Add '-7' to each side of the equation.
7 + -7 + -3r = 10 + -7

Combine like terms: 7 + -7 = 0
0 + -3r = 10 + -7
-3r = 10 + -7

Combine like terms: 10 + -7 = 3
-3r = 3

Divide each side by '-3'.
r = -1

Simplifying
r = -1

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