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10-(x-2)=3(5x+1)-4x
We move all terms to the left:
10-(x-2)-(3(5x+1)-4x)=0
We get rid of parentheses
-x-(3(5x+1)-4x)+2+10=0
We calculate terms in parentheses: -(3(5x+1)-4x), so:We add all the numbers together, and all the variables
3(5x+1)-4x
We add all the numbers together, and all the variables
-4x+3(5x+1)
We multiply parentheses
-4x+15x+3
We add all the numbers together, and all the variables
11x+3
Back to the equation:
-(11x+3)
-1x-(11x+3)+12=0
We get rid of parentheses
-1x-11x-3+12=0
We add all the numbers together, and all the variables
-12x+9=0
We move all terms containing x to the left, all other terms to the right
-12x=-9
x=-9/-12
x=3/4
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