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10-0.5w=1/2w-10
We move all terms to the left:
10-0.5w-(1/2w-10)=0
Domain of the equation: 2w-10)!=0We get rid of parentheses
w∈R
-0.5w-1/2w+10+10=0
We multiply all the terms by the denominator
-(0.5w)*2w+10*2w+10*2w-1=0
We add all the numbers together, and all the variables
-(+0.5w)*2w+10*2w+10*2w-1=0
We multiply parentheses
-0w^2+10*2w+10*2w-1=0
Wy multiply elements
-0w^2+20w+20w-1=0
We add all the numbers together, and all the variables
-1w^2+40w-1=0
a = -1; b = 40; c = -1;
Δ = b2-4ac
Δ = 402-4·(-1)·(-1)
Δ = 1596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1596}=\sqrt{4*399}=\sqrt{4}*\sqrt{399}=2\sqrt{399}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-2\sqrt{399}}{2*-1}=\frac{-40-2\sqrt{399}}{-2} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+2\sqrt{399}}{2*-1}=\frac{-40+2\sqrt{399}}{-2} $
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