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10-0.5x=1/3x
We move all terms to the left:
10-0.5x-(1/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-0.5x-(+1/3x)+10=0
We get rid of parentheses
-0.5x-1/3x+10=0
We multiply all the terms by the denominator
-(0.5x)*3x+10*3x-1=0
We add all the numbers together, and all the variables
-(+0.5x)*3x+10*3x-1=0
We multiply parentheses
-0x^2+10*3x-1=0
Wy multiply elements
-0x^2+30x-1=0
We add all the numbers together, and all the variables
-1x^2+30x-1=0
a = -1; b = 30; c = -1;
Δ = b2-4ac
Δ = 302-4·(-1)·(-1)
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-8\sqrt{14}}{2*-1}=\frac{-30-8\sqrt{14}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+8\sqrt{14}}{2*-1}=\frac{-30+8\sqrt{14}}{-2} $
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