10-16v=-6v2

Solution for 10-16v=-6v2 equation:

10-16v=-6v^2

We move all terms to the left:

10-16v-(-6v^2)=0

We get rid of parentheses

6v^2-16v+10=0

a = 6; b = -16; c = +10;
Δ = b2-4ac
Δ = -162-4·6·10
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4}{2*6}=\frac{12}{12}
=1
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4}{2*6}=\frac{20}{12}
=1+2/3
$