10-2(2,5-13,5x)-6x=140-(11x+7)

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Solution for 10-2(2,5-13,5x)-6x=140-(11x+7) equation: 



10-2(2.5-13.5x)-6x=140-(11x+7)

We move all terms to the left:

10-2(2.5-13.5x)-6x-(140-(11x+7))=0

We add all the numbers together, and all the variables

-2(-13.5x+2.5)-6x-(140-(11x+7))+10=0

We add all the numbers together, and all the variables

-6x-2(-13.5x+2.5)-(140-(11x+7))+10=0

We multiply parentheses

-6x+26x-(140-(11x+7))-5+10=0



We calculate terms in parentheses: -(140-(11x+7)), so:

140-(11x+7)

determiningTheFunctionDomain
-(11x+7)+140

We get rid of parentheses

-11x-7+140

We add all the numbers together, and all the variables

-11x+133

Back to the equation:

-(-11x+133)



We add all the numbers together, and all the variables

20x-(-11x+133)+5=0

We get rid of parentheses

20x+11x-133+5=0

We add all the numbers together, and all the variables

31x-128=0

We move all terms containing x to the left, all other terms to the right

31x=128

x=128/31

x=4+4/31

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