10-2(2x+1)=(x-2)

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Solution for 10-2(2x+1)=(x-2) equation: 



10-2(2x+1)=(x-2)

We move all terms to the left:

10-2(2x+1)-((x-2))=0

We multiply parentheses

-4x-((x-2))-2+10=0



We calculate terms in parentheses: -((x-2)), so:

(x-2)

We get rid of parentheses

x-2

Back to the equation:

-(x-2)



We add all the numbers together, and all the variables

-4x-(x-2)+8=0

We get rid of parentheses

-4x-x+2+8=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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